dongyi7513 2013-06-28 17:21 采纳率: 100%
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Php Exec功能

I am unable to understand why the return value in php is not working. Can anybody help me?

<?php
exec("xyz.py",$output,$return);
foreach($output as $item){
echo "$item"; 
}
echo $return;
?>

The script of xyz.py is as follows:

def func():
  print ('Hello')
  return 21
func()

The output is always Hello0 no matter what value xyz.py returns

Thanks in advance.

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3条回答 默认 最新

  • dongquan6030 2013-06-28 17:24
    关注

    According to the PHP docs, the third argument of exec, ($return in your example), works like this:

    If the return_var argument is present along with the output argument, then the return status of the executed command will be written to this variable

    Since your python program ran fine, the return status should be 0 (no errors).

    This might be what you want:

    import sys
    def func():
      print ('Hello')
      return 21
    sys.exit(func())
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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