带有可变函数名称的PHP模糊代码

Question

Consider the following

Class someController {

    public static $layout = 'index';
}

Then in another scope

$layout = 'default';
$controller = 'someController';

if(property_exists($controller, 'layout')){
    $layout = $controller::$layout;
}

What will then be the content of $layout? Is it going to try to access someController::$layout or someController::default?

Answer 1

When PHP parses the code, the referencing of the static class variable takes preference over the standalone variable.

Edit: Infact, the parser does not even consider to think $controller::$layout has a reference to the $layout variable as it is using :: as @Paul Crovella mentioned in the question comments.