PHP从数组中提取值并将它们传递给函数

Question

I'm trying to extract values from an array, and pass them to a function where they'll be used. I've used echo inside the function for this example.

I'm using extract to get all the values.

Thing is, this wont work. Do you see how this can be done?

<?php

$my_array = array("a" => "Prince", "b" => "Funky"); // around 10 more

$g = extract($my_array);

foo($g);

function foo($g) {
    echo 'My name is '.$a.', and I am '.$b;
}

?>

Answer 1

Functions in PHP have a different scope, so the variables $a, $b etc. aren't available inside your function. Trying to use them inside the function would result in Undefined variable notices (if you enable error reporting, that is).

Right now, you're storing the return value of extract() (which is the total number of variables parsed) into your function. You want the values instead, so change your function like so:

function foo($array) {
    extract($array);
    echo 'My name is '.$a.', and I am '.$b;
}

Note that I've moved the extract() call inside the function. This way, you wouldn't pollute the global scope with random variables (which may have undesired results and will make your debugging hard for no reason).

Now you can call your function, like so:

foo($my_array);

Output:

My name is Prince, and I am Funky

Demo

It's better to avoid extract() altogether, though. See: What is so wrong with extract()?