如何在Code Igniter查询中简明地返回第一个结果？

Question

I tried to return an object representing a journal retrieved based on its ID in a model.

public function getJournal($id) {
    $query = $this->db->query("SELECT * FROM journals WHERE id='$id'");
    return ($query->num_rows() == 1) ? ($query->result())[0] : NULL;
}

However, PHP issues an error declaring an unexpected open right bracket ([).

I ended up actually looping through the array of 1 object entity to return it, which is silly but works.

public function getJournal($id) {
    $query = $this->db->query("SELECT * FROM journals WHERE id='$id'");
    if ($query->num_rows() == 1) {
        foreach ($query->result() as $journal)
            return $journal;
    }
    else
        return NULL;
}

What is a more concise way to return this object?

Answer 1

Instead of grabbing the result(), just use the row() method:

$first_result = $query->row();