I have an array of arrays as follows (for example)
$array = (
[0] => array (
[a_key] => 123456,
[b_key] => First Name,
[c_key] => Last Name,
[this_key ] => Institution,
),
[1] => array (
[a_key] => 123456,
[b_key] => First Name,
[c_key] => Last Name,
[this_key ] => Institution,
),
[2] => array (
[a_key] => 123456,
[b_key] => First Name,
[c_key] => Last Name,
[this_key ] => Institution,
),
)
And I want to check if $array[$key]['this_key'] is not null or does not equal '' when
$key = (any number)
How do I set $key to match any number so that the following returns true when at least one second-dimension-array in the array has [this_key] set?
if( $array[$key]['this_key'] != '' )
echo "true";
else
echo "false";
So, if $array[0][this_key] is not set, $array[1][this_key] IS set, and $array[2][this_key] is not set, the IF statement will return true because at least ONE of all of the arrays has [this_key] set.
Edit:
To give some context to the situation and provide a specific scenario to which this solution could be applied:
I have a list of people in a database that I need to display. For each person, I have a first and last name, and optionally an institution/degree/job title held by the individual. These need to display like this:
Without a title:
John Smith, Jane Doe, Fred Nerk
With a title:
John Smith, Penologist; Jane Doe, Professor; Fred Nerk, Astrophysicist
With mixed cases of a title:
John Smith; Jane Doe, Professor; Fred Nerk
Note the punctuation used in each case. If there is no optional information for ANY record, a comma separates the individuals. If there is optional information for ONE OR MORE records, a semicolon separates the individuals.
With the if statement, I would be able to determine if one of the individuals has optional information, even if every other individual does not.
By the way:
This PHP Sandbox Tool was incredibly useful for testing PHP code before integrating it into my file. It supports PHP versions from 4.4.9 up to 5.5.5.