doulu7174 2012-05-16 16:07
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为什么PHP挂起,当一个bash调用分叉

I am calling some bash code from php, but even though I fork the bash (with &), the php will not finish before the full bash is done.

This code:

<html>
<body>
HTML START<br>
<pre>
<?php
echo "PHP START
";
echo `sleep 30 &`;
echo "PHP END
";
?>
</pre>
HTML END<br>
</body>
</html>

Will not show anything in the browser, before after 30 seconds.

What I really want is to start a GUI app from php, that should continue to run.

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5条回答 默认 最新

  • duancheng8000 2012-05-16 16:17
    关注

    Close all file descriptors in your sleep call to allow it to detach:

    <?php
    echo "PHP START
    ";
    echo `sleep 30 <&- 1<&- 2<&- &`;
    echo "PHP END
    ";
    ?>
    

    Otherwise, the output file descriptor is still open, and PHP is still trying to wait to receive its output, even with the process no longer attached directly.

    This works correctly when run, immediately exiting but leaving a sleep process behind:

    $ time php5 test.php; ps auxw | grep sleep | grep -v grep
    PHP START
    PHP END
    
    real    0m0.019s
    user    0m0.008s
    sys         0m0.004s
    cduffy    6239  0.0  0.0  11240   576 pts/0    S    11:23   0:00 sleep 30
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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