PHP检测页面类型/类别

Question

I was wondering if their was any sort of way to detect a pages genre/category.

Possibly their is a way to find keywords or something?

Unfortunately I don't have any idea so far, so I don't have any code to show you.

But if anybody has any ideas at all, let me know.

Thanks!

EDIT @Nican

Perhaps their is a way to set, let's say 10 category's (Entertainment, Funny, Tech).

Then creating keywords for these category's (Funny = Laughter, Funny, Joke etc).

Then searching through a webpage (maybe using a cUrl) for these keywords and assigning it to the right category.

Hope that makes sense.

Answer 1

Folksonomy may be a way of accomplishing what you're looking for:

http://en.wikipedia.org/wiki/Folksonomy

For instance, in Drupal they have a Folksonomy module:

http://drupal.org/node/19697 (Note this module appears to be dead, see http://drupal.org/taxonomy/term/71)

Couple that with a tag cloud generator, and you may get somewhere:

http://drupal.org/project/searchcloud

Plus, a little more complexity may be able to derive mapped relationships to other terms, especially if you control the structure of the tagging options.

http://intranetblog.blogware.com/blog/_archives/2008/5/22/3707044.html

EDIT

In general, the type of system you're trying to build relies on unique word values on a page. So you would need to...

1. Get unique word values from your content (index values or create a bot to crawl your site)
2. Remove all words and symbols you can't use (at, the, or, and, etc...)
3. Count the number of times the unique words appear on the page
4. Add them to some type of datastore so you can call them based on the relationships you're mapping
5. If you have a root label system in place, associate those values with the word counts on the page (such as a query or derived table)

This is very general, and there are a number of ways this can be implemented/interpreted. Folksonomies are meant to "crowdsource" much of the effort for you, in a "natural way", as long as you have a user base that will contribute.