python获取邮箱的内容后,怎么取到里面的验证码

Question

连接到POP3服务器:

server = poplib.POP3(pop3_server)

可以打开或关闭调试信息:

server.set_debuglevel(1)

可选:打印POP3服务器的欢迎文字:

print(server.getwelcome().decode('utf-8'))

身份认证:

server.user(email)
server.pass_(password)

stat()返回邮件数量和占用空间:

print('Messages: %s. Size: %s' % server.stat())

list()返回所有邮件的编号:

resp, mails, octets = server.list()

可以查看返回的列表类似[b'1 82923', b'2 2184', ...]

print(mails)

获取最新一封邮件, 注意索引号从1开始:

index = len(mails)
resp, lines, octets = server.retr(index)

lines存储了邮件的原始文本的每一行,

可以获得整个邮件的原始文本:

msg_content = b'\r\n'.join(lines).decode('utf-8')

稍后解析出邮件:

msg = Parser().parsestr(msg_content)
print_info(msg)

全部源码如下：

-*- coding: utf-8 -*-

from email.parser import Parser
from email.header import decode_header
from email.utils import parseaddr

import poplib

import requests
import json

import re

输入邮件地址, 口令和POP3服务器地址:

email = "[e-mail]"
password = "abcdefg"
pop3_server = "pop.qq.com"

文本邮件的内容也是str，还需要检测编码，否则，非UTF-8编码的邮件都无法正常显示

def guess_charset(msg):
charset = msg.get_charset()
if charset is None:
content_type = msg.get('Content-Type', '').lower()
pos = content_type.find('charset=')
if pos >= 0:
charset = content_type[pos + 8:].strip()
return charset

def decode_str(s):

decode_header()返回一个list 偷懒，只取了第一个元素

value, charset = decode_header(s)[0]
if charset:
    value = value.decode(charset)
return value

def print_info(msg, indent=0):
if indent == 0:
for header in ['From', 'To', 'Subject']:
value = msg.get(header, '')
if value:
if header=='Subject':
value = decode_str(value)
else:
hdr, addr = parseaddr(value)
name = decode_str(hdr)
value = u'%s <%s>' % (name, addr)
print('%s%s: %s' % (' ' * indent, header, value))
if (msg.is_multipart()):
parts = msg.get_payload()
for n, part in enumerate(parts):
print('%spart %s' % (' ' * indent, n))
print('%s--------------------' % (' ' * indent))
print_info(part, indent + 1)
else:
content_type = msg.get_content_type()
if content_type=='text/plain' or content_type=='text/html':
content = msg.get_payload(decode=True)
charset = guess_charset(msg)
if charset:
content = content.decode(charset)
print('%sText: %s' % (' ' * indent, content + '...'))
else:
print('%sAttachment: %s' % (' ' * indent, content_type))

连接到POP3服务器:

server = poplib.POP3(pop3_server)

可以打开或关闭调试信息:

server.set_debuglevel(1)

可选:打印POP3服务器的欢迎文字:

print(server.getwelcome().decode('utf-8'))

身份认证:

server.user(email)
server.pass_(password)

stat()返回邮件数量和占用空间:

print('Messages: %s. Size: %s' % server.stat())

list()返回所有邮件的编号:

resp, mails, octets = server.list()

可以查看返回的列表类似[b'1 82923', b'2 2184', ...]

print(mails)

获取最新一封邮件, 注意索引号从1开始:

index = len(mails)
resp, lines, octets = server.retr(index)

lines存储了邮件的原始文本的每一行,

可以获得整个邮件的原始文本:

msg_content = b'\r\n'.join(lines).decode('utf-8')\

稍后解析出邮件:

msg = Parser().parsestr(msg_content)
print_info(msg)

Answer 1

import re

str =msg
print (re.findall(r"\d{6}",str))