dqwh0108 2017-12-28 06:16
浏览 98
已采纳

运行localhost时php中出错

Following error in php while running through localhost

Warning: mysqli_select_db() expects parameter 1 to be mysqli, string given in C:\xampp\htdocs\IVPORTAL\admin\include\database.php on line 9

Warning: mysqli_error() expects exactly 1 parameter, 0 given in C:\xampp\htdocs\IVPORTAL\admin\include\database.php on line 9

i didn't get the error.

<?php 
require_once("config.php");

class database { 
    private $link;

    function __construct() {
        $this->link = mysqli_connect(config::host,config::username,config::passwor‌​d);
        mysqli_select_db(config::database,$this->link) or die(mysqli_error()); 
    } 

    function __distruct() {
        mysqli_close($this->link);
    } 
  • 写回答

2条回答 默认 最新

  • dongwei5794 2017-12-28 06:37
    关注

    from the error it looks like you have missing params for function mysqli_error

    following is syntax to use mysqli_error

    mysqli_error(connection);
    
    //change it to following
    mysqli_error($this->link)
    

    for the reference i have update your code

    require_once("config.php"); 
    class database { 
        private $link; 
    
        function __construct() {
            $this->link = mysqli_connect(config::host,config::username,config::passwor‌​d); 
            mysqli_select_db(config::database,$this->link) or die(mysqli_error($this->link)); 
        } 
    
        function __distruct() { 
            mysqli_close($this->link); 
    }
    

    it should work

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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