dongtiannan0367 2015-04-26 10:14
浏览 193
已采纳

表单写入mysql数据库

I'm currently working on writing a form to a database, still a beginner. I attempted a form that i will show below but it seems to give me errors. If anyone could help me find out what is wrong with my PHP code then it would be great. Thanks in advance:

My form.php

<form method="post" action="db.php" name="OverrideForm" id="OverrideForm" autocomplete="on">
    <fieldset>
        <legend>Contact Details</legend>
        <div>
            <label for="name" accesskey="N">First Name</label>
            <input name="name" type="text" id="name" required />
        </div>
        <div>
            <label for="mname" accesskey="M">Middle Name</label>
            <input name="mname" type="text" id="mname" required />
        </div>
        <div>
            <label for="fname" accesskey="F">Last Name</label>
            <input name="fname" type="text" id="fname" required />
        </div>
        <div>
            <label for="sid" accesskey="i">Student ID</label>
            <input name="sid" type="text" id="sid" size="10"  required />
        </div>
<div>
            <label for="email" accesskey="E">Email</label>
            <input name="email" type="email" id="email" pattern="^[A-Za-z0-9](([_\.\-]?[a-zA-Z0-9]+)*)@([A-Za-z0-9]+)(([\.\-]?[a-zA-Z0-9]+)*)\.([A-Za-z]{2,})$" required />
        </div>
        <div>
            <label for="phone" accesskey="p">Phone Number</label>
            <input name="phone" type="text" id="phone" size="8"  required />
        </div>
<div>
            <label for="sc" accesskey="s">Scolarship</label>
            <select name="sc" id="sc" required="required">
                <option value="0">Yes</option>
                <option value="1">No</option>
            </select>
        </div>            
   </fieldset>

    <fieldset>
        <legend>Subject Details</legend>
<div>
            <label for="class" accesskey="c">Class</label>
            <input name="class" type="text" id="class" size="50" required />
        </div>
        <div>
            <label for="section" accesskey="o">Section</label>
            <input name="section" type="text" id="section" size="1" required />
        </div>
        <div>
            <label for="semester" accesskey="S">Semester</label>
            <select name="semester" id="semester" required="required">
                <option value="F15">Fall 2015</option>
                <option value="S15">Summer 2015</option>
                <option value="SP16">Spring 2016</option>
            </select>
        </div>
    </fieldset>

    <input type="submit" class="submit" id="submit" value="Submit" />
</form>

my db.php

    <?php
$mysql_host     = "localhost";
$mysql_username = "blahblah";
$mysql_password = "blahblah";
$mysql_database = "blahblah";

$mysqli  = new Mysqli($mysql_host, $mysql_username, $mysql_password, $mysql_database) or die(mysql_error());
$prepare = $mysqli->prepare("INSERT INTO `Overrides`(`name`,`mname`,`fname`,`sid`,`email`,`phone`,`sc`,`class`,`section`,`semester`) VALUES ('$name','$mname','$fname','$sid','$email','$phone','$sc','$class','$section','$semester')");
$prepare->bind_param("ssssssssss", $_POST['name'], $_POST['mname'], $_POST['fname'], $_POST['sid'], $_POST['email'], $_POST['phone'], $_POST['sc'], $_POST['class'], $_POST['section'], $_POST['semester']);
$prepare->execute();
print_r($_POST)
?>

Error i'm getting is:

Warning: mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement in /home/aukwizcq/public_html/db.php on line 9
Array ( [name] => aaa [mname] => aaa [fname] => aaaa [sid] => 123456 [email] => fgfg@hotmail.com [phone] => 45454 [sc] => 1 [class] => Cpeg 340 [section] => 1 [semester] => S15 )

My db structure:

Name Type Collation Attributes Null Default Extra Action

1   name    varchar(30) latin1_swedish_ci       No  None        Change 
2   mname   varchar(30) latin1_swedish_ci       No  None        Change 
3   fname   varchar(30) latin1_swedish_ci       No  None        Change 
4   sid varchar(11) latin1_swedish_ci       No  None        Change Change   
5   email   varchar(50) latin1_swedish_ci       No  None        Change 
6   phone   int(8)          No  None        Change Change   Drop Drop   
7   sc  bit(1)          No  None        Change Change   Drop Drop   
8   class   varchar(10) latin1_swedish_ci       No  None        Change 
9   section int(1)          No  None        Change Change   Drop Drop   
10  semester    varchar(11) latin1_swedish_ci       No  None        Change 
  • 写回答

1条回答 默认 最新

  • duanlingzei0170 2015-04-26 10:16
    关注

    The syntax of the prepared statement is not right, the variables should be question marks. It should be like this:

    $prepare = $mysqli->prepare("INSERT INTO `Overrides`(`name`,`mname`,`fname`,`sid`,`email`,`phone`,`sc`,`class`,`section`,`semester`) VALUES (?,?,?,?,?,?,?,?,?,?)");
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 微信会员卡接入微信支付商户号收款
  • ¥15 如何获取烟草零售终端数据
  • ¥15 数学建模招标中位数问题
  • ¥15 phython路径名过长报错 不知道什么问题
  • ¥15 深度学习中模型转换该怎么实现
  • ¥15 HLs设计手写数字识别程序编译通不过
  • ¥15 Stata外部命令安装问题求帮助!
  • ¥15 从键盘随机输入A-H中的一串字符串,用七段数码管方法进行绘制。提交代码及运行截图。
  • ¥15 TYPCE母转母,插入认方向
  • ¥15 如何用python向钉钉机器人发送可以放大的图片?