duanhe7471 2012-11-21 11:20
浏览 22
已采纳

xml如何在php中解析

I have this xml

http://www.scorespro.com/rss/live-soccer.xml

the structure is this :

 <rss>
 <channel>
 <item>
 <title>
 </title>
 </item>
 </channel>
 </rss>

I want to get the information about the titles, so i'm trying to do this, but without success.

  $xml = simplexml_load_file('http://www.scorespro.com/rss/live-soccer.xml');
foreach($xml->item as $item)
 {
 echo $item->title;
 } 

I already did print_r($xml) to see if is parsing correctly the url that i'm giving.

  • 写回答

1条回答 默认 最新

  • dtrotfd1012 2012-11-21 11:24
    关注

    $xml has root node, in this case <rss>:

    foreach($xml->channel->item as $item)
    

    You can also use XPath to get the items:

    $items = $result = $xml->xpath('/rss/channel/item');
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥20 求各位懂行的人,注册表能不能看到usb使用得具体信息,干了什么,传输了什么数据
  • ¥15 个人网站被恶意大量访问,怎么办
  • ¥15 Vue3 大型图片数据拖动排序
  • ¥15 Centos / PETGEM
  • ¥15 划分vlan后不通了
  • ¥15 GDI处理通道视频时总是带有白色锯齿
  • ¥20 用雷电模拟器安装百达屋apk一直闪退
  • ¥15 算能科技20240506咨询(拒绝大模型回答)
  • ¥15 自适应 AR 模型 参数估计Matlab程序
  • ¥100 角动量包络面如何用MATLAB绘制