duanemei2194 2017-09-21 12:38
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我如何将变量从php传递给js作为变量(名称)本身而不是字符串?

I am passing data from php to js via ajax. I use json_encode before the transfer. here the example:

$data = [
    [
        "path" => "/TestMenu1",
        "component" => 'test1',
        "children" => [[
            "path" => "/api/sub/route",
            "component" => "test2",
        ]]
    ],[
        "path" => "/api/findme/2",
        "component" => "test3",
    ]
]; 

And from client side I get this without any problems:

[
  {
    "path": "/TestMenu1",
    "component": "test1",
    "children": [
      {
        "path": "/api/sub/route",
        "component": "test2"
      }
    ]
  },
  {
    "path": "/api/findme/2",
    "component": "test3"
  }
]

But I need the components to be variable names instead string like:

[
  {
    "path": "/TestMenu1",
    "component": test1,
    "children": [
      {
        "path": "/api/sub/route",
        "component": test2
      }
    ]
  },
  {
    "path": "/api/findme/2",
    "component": test3
  }
]

Is that possible? If yes how can I accomplish that?

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4条回答 默认 最新

  • dongpo7467 2017-09-21 12:55
    关注

    You will need to make intermediate transformation of response you get from server to extended data structure with component name replaced with real component instance. For this make sure components are available in helper object map and individual component objects are accessible by its name.

    Here is simple example of this approach:

    // Response you get from server
    const response = [
      {
        "path": "/TestMenu1",
        "component": "test1",
        "children": [
          {
            "path": "/api/sub/route",
            "component": "test2"
          }
        ]
      },
      {
        "path": "/api/findme/2",
        "component": "test3"
      }
    ]
    
    // Map of component name to component instance
    const components = {
      test1: { name: 'test1' },
      test2: { name: 'test2' },
      test3: { name: 'test3' }
    }
    
    // Recursive function to resolve component by its name from the map
    const mapComponents = (items, componentMap) => {
      return items.map(item => {
        item.component = componentMap[item.component]
        
        if (item.children && item.children.length) {
          item.children = mapComponents(item.children, componentMap)
        }
        
        return item
      })
    }
    
    // Final result
    const result = mapComponents(response, components)
    
    console.log(result)
    .as-console-wrapper {min-height: 100%}

    </div>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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