duanben1909 2012-09-16 21:38
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使用preg_match_all从字符串中提取Image SRC

I have a string of data that is set as $content, an example of this data is as follows

This is some sample data which is going to contain an image in the format <img src="http://www.randomdomain.com/randomfolder/randomimagename.jpg">.  It will also contain lots of other text and maybe another image or two.

I am trying to grab just the <img src="http://www.randomdomain.com/randomfolder/randomimagename.jpg"> and save it as another string for example $extracted_image

I have this so far....

if( preg_match_all( '/<img[^>]+src\s*=\s*["\']?([^"\' ]+)[^>]*>/', $content, $extracted_image ) ) {
$new_content .= 'NEW CONTENT IS '.$extracted_image.'';

All it is returning is...

NEW CONTENT IS Array

I realise my attempt is probably completly wrong but can someone tell me where I am going wrong?

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  • dongqian5639 2018-11-16 23:21
    关注

    Using regex to parse valid html is ill-advised. Because there can be unexpected attributes before the src attribute, because non-img tags can trick the regular expression into false-positive matching, and because attribute values can be quoted with single or double quotes, you should use a dom parser. It is clean, reliable, and easy to read.

    Code: (Demo)

    $string = <<<HTML
This is some sample data which is going to contain an image
in the format <img src="http://www.randomdomain.com/randomfolder/randomimagename.jpg">.
It will also contain lots of other text and maybe another image or two
like this: <img alt='another image' src='http://www.example.com/randomfolder/randomimagename.jpg'>
HTML;

$srcs = [];
$dom=new DOMDocument;
$dom->loadHTML($string);
foreach ($dom->getElementsByTagName('img') as $img) {
    $srcs[] = $img->getAttribute('src');
}

var_export($srcs);

    Output:

    array (
  0 => 'http://www.randomdomain.com/randomfolder/randomimagename.jpg',
  1 => 'http://www.example.com/randomfolder/randomimagename.jpg',
)
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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