如果strpos不完全错误，如何返回true？

Question

I know how strpos works, and it is working as expected, but the return in the if function isn't.

Some code:

foreach ($socialstream as $key => $social) {
    //filtering in here
    $result= $this->search_objects($social);
    ....
}

My function search_objects:

function search_objects($objects)
{
    $filters = array('word', 'test');
    foreach ($objects as $key => $value) {
        if (is_array($value) || is_object($value)) {
            $this->search_objects($value);
        } else {
            //look for faulty strings in value
            foreach ($filters as $filter) {
                if (!is_int($value) && strpos($value, $filter) !== false) {
                    return true;
                }
            }

        }
    }
    return false;
}

If I print out my $result, I always get false back, instead of the true in the if function. I know it gets to the if when the needle exists in the haystack, by debugging, it's just not returning it.

What am I missing?

Answer 1

I think your problem has to do with the recursive part:

    if (is_array($value) || is_object($value)) {
        $this->search_objects($value);
    }

You probably want to do something with the return value. Like: if ($this->search_objects($value)) return true;

(Then again, I'm not sure what you are trying to accomplish)

edit: Try this:

function search_objects($objects)
{
    $filters = array('word', 'test');
    foreach ($objects as $key => $value) {
        if (is_array($value) || is_object($value)) {
            if ($this->search_objects($value)) {
                return true;
            }
        } else {
            //look for faulty strings in value
            foreach ($filters as $filter) {
                if (!is_int($value) && strpos($value, $filter) !== false) {
                    return true;
                }
            }

        }
    }
    return false;
}