douti0467 2015-11-29 20:59
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检查电子邮件是否已激活不工作[关闭]

I just created a script that is checking if the user has already activated his account. If so, it should say "The account has already been activated" and if not then activate that account. The problem is it always says "Activation was successful." Can someone help me please?

<?php
session_start();
include_once 'dbconnect.php';
$dbconnect = mysqli_connect('server', 'user', 'password', 'database');

if (isset($_GET['email'])) {
    $email = $_GET['email'];
}
if (isset($_GET['status']) && (strlen($_GET['status']) == 32)) {
    $status = $_GET['status'];
}

if (isset($email) && isset($status)) {

    $sql = "SELECT status FROM users WHERE email='$email'";
    $result = mysql_query($sql);

    if ($result == 'active') {

        echo" <div style='position:absolute;left:29.5%;top:10%;width:41%;' class='alert alert-danger'>
             <a href='#' class='close' data-dismiss='alert' aria-label='close'>&times;</a>
             <strong>Chyba!</strong> &#218;&#269;et je ji&#158; aktivov&#225;n!
             </div>";
    } else {

        $query_activate_account = "UPDATE users SET status='active' WHERE(email ='$email' AND status='$status')";
        $result_activate_account = mysqli_query($dbconnect, $query_activate_account);

        echo" <div style='position:absolute;left:29.5%;top:10%;width:41%;' class='alert alert-success'>
             <a href='#' class='close' data-dismiss='alert' aria-label='close'>&times;</a>
             <strong>Úspěch!</strong> Aktivace proběhla úspěšně! <a href='signin.php'>Přihlášení</a>
             </div>";
    }
}
?>
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1条回答 默认 最新

  • duanpin5168 2015-11-29 21:02
    关注

    Update

     $sql = "SELECT status FROM users WHERE email='$email'";
        $result = mysql_query($sql);
    to 
     $sql = "SELECT status FROM users WHERE email='$email'";
        $result = mysql_query($sql);
    while($row = mysql_fetch_assoc($result )){
      $status = $row['status'];
    }
    

    And replace

    if ($result == 'active') {
    

    with

    if ($status== 'active') {
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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