Golang记录http响应（除了请求）

Question

I am using Go and the Gorilla web toolkit's mux and handler packages to build a complex application, part of which requires a http server. Gorilla's mux and handler packages work wonderfully and I am able to successfully get the http server up and running and it has been quite simple to log requests.

However, I am unable to determine how I may log responses. Ideally, I would like a mechanism, similar to Gorilla's LoggingHandler, that "wraps" the logging mechanism easily.

Is there a Golang package that does easily wraps / logs responses? Is there a way to use Go or Gorilla's capabilities in this fashion that I have not considered?

Answer 1

Thanks for the great suggestions. I tried a few of the suggestions and landed on a rather simple solution that uses a minimalist wrapper. Here is the solution that worked for me (feel free to offer comments, or better yet, other solutions):

import (
    "fmt"
    "log"
    "net/http"
    "net/http/httptest"
    "net/http/httputil"
    "github.com/gorilla/mux"
)
:

func logHandler(fn http.HandlerFunc) http.HandlerFunc {
    return func(w http.ResponseWriter, r *http.Request) {
        x, err := httputil.DumpRequest(r, true)
        if err != nil {
            http.Error(w, fmt.Sprint(err), http.StatusInternalServerError)
            return
        }
        log.Println(fmt.Sprintf("%q", x))
        rec := httptest.NewRecorder()
        fn(rec, r)
        log.Println(fmt.Sprintf("%q", rec.Body))            
    }
}

func MessageHandler(w http.ResponseWriter, r *http.Request) {
    fmt.Fprintln(w, "A message was received")
}

And the following code will use the aforementioned handler:

:
router := mux.NewRouter()
router.HandleFunc("/", logHandler(MessageHandler))
:

Output from the above code will be something along the lines of:

:
2016/07/20 14:44:29 "GET ... HTTP/1.1
Host: localhost:8088
Accept: */*
User-Agent: curl/7.43.0

"
2016/07/20 14:44:29 ...[response body]
: