Golang标志被解释为第一个os.Args参数

Question

I would like to run my program like this:

go run launch.go http://example.com --m=2 --strat=par

"http://example.com" gets interpreted as the first command line argument, which is ok, but the flags are not parsed after that and stay at the default value. If I put it like this:

go run launch.go --m=2 --strat=par http://example.com

then "--m=2" is interpreted as the first argument (which should be the URL).

I could also just remove the os.Args completely, but then I would have only optional flags and I want one (the URL) to be mandatory.

Here's my code:

package main

import (
    "fmt"
    "webcrawler/crawler"
    "webcrawler/model"
    "webcrawler/urlutils"
    "os"
    "flag"
)

func main() {
    if len(os.Args) < 2 {
        log.Fatal("Url must be provided as first argument")
    }

    strategy := flag.String("strat", "par", "par for parallel OR seq for sequential crawling strategy")
    routineMultiplier := flag.Int("m", 1, "Goroutine multiplier. Default 1x logical CPUs. Only works in parallel strategy")

    page := model.NewBasePage(os.Args[1])
    urlutils.BASE_URL = os.Args[1]
    flag.Parse()
    pages := crawler.Crawl(&page, *strategy, *routineMultiplier)
    fmt.Printf("Crawled: %d
", len(pages))
}

I am pretty sure that this should be possible, but I can't figure out how.

EDIT: Thanks justinas for the hint with the flag.Args(). I now adapted it like this and it works:

...
flag.Parse()

args := flag.Args()
    if len(args) != 1 {
        log.Fatal("Only one argument (URL) allowed.")
    }

page := model.NewBasePage(args[0])
...

Answer 1

os.Args doesn't really know anything about the flag package and contains all command-line arguments. Try flag.Args() (after calling flag.Parse(), of course).