Go's math/random
library is missing a function to generate 64-bit numbers. This has been an open issue for about four years. In the meantime, what does a workaround look like?
如何在Go中生成随机uint64?
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3条回答 默认 最新
- douhuan1905 2016-09-28 19:41关注
The easiest would be to call
rand.Uint32()
twice:func Uint64() uint64 { return uint64(rand.Uint32())<<32 + uint64(rand.Uint32()) }
Another option is to call
rand.Read()
(was added in Go 1.7) to read 8 bytes, then use theencoding/binary
package to obtain auint64
value from it:func Uint64() uint64 { buf := make([]byte, 8) rand.Read(buf) // Always succeeds, no need to check error return binary.LittleEndian.Uint64(buf) }
Note: as the doc of
rand.Read()
states, it always reads as many bytes as the length of the passed slice, and it always returnsnil
error, so no need to check error in this case.Note #2: you could also use
binary.BigEndian
instead ofbinary.LittleEndian
, as we're generating a random number using all its bytes, order of bytes is completely irrelevant.本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报
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