“＆^”运算符是什么意思？

Question

I am a newbie of golang, and confused with the "&^" operator.

From the spec, the explanation of "&^" is: bit clear (AND NOT). Per my understanding, it means: x &^ y == x & (^y).

Is my understanding right? Thanks!

Answer 1

Your'understanding is right. You can make it as a "bit operator" And the rules:

1 &^ 1 = 0
1 &^ 0 = 1
0 &^ 0 = 0
0 &^ 1 = 0

Just like x & y, x ^ y, x | y.