doumianfeng6979 2018-02-23 17:26
浏览 67
已采纳

如何实现对非缓冲通道的非阻塞写入?

From Effective Go

Receivers always block until there is data to receive. If the channel is unbuffered, the sender blocks until the receiver has received the value.

But signal.Notify relays signals to an unbuffered channel without blocking. How does this work and is it possible to do with other chan<- types ?

  • 写回答

2条回答 默认 最新

  • dongzhanlu0658 2018-02-23 17:29
    关注

    What it means when it says os.Notify will not block is the messages will be dropped were it to block. So while it's true that it doesn't block, it's not true that it will relay the signals if they can't be received immediately. This is done via simple select:

    select {
        case channel <- message:
            // message sent
        default:
            // message dropped
    }
    

    Which is why the documentation for Notify explicitly states that you should use a buffered channel. Also note that buffered channels can also block, not just unbuffered channels; buffered channels only block if the buffer is already full.

    select is covered in the tour and the spec.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥20 wireshark抓不到vlan
  • ¥20 关于#stm32#的问题:需要指导自动酸碱滴定仪的原理图程序代码及仿真
  • ¥20 设计一款异域新娘的视频相亲软件需要哪些技术支持
  • ¥15 stata安慰剂检验作图但是真实值不出现在图上
  • ¥15 c程序不知道为什么得不到结果
  • ¥40 复杂的限制性的商函数处理
  • ¥15 程序不包含适用于入口点的静态Main方法
  • ¥15 素材场景中光线烘焙后灯光失效
  • ¥15 请教一下各位,为什么我这个没有实现模拟点击
  • ¥15 执行 virtuoso 命令后,界面没有,cadence 启动不起来