Golang程序在Windows 10中给出了不正确的结果

Question

First of all, I am a newbie to Go programming. I have a simple Golang program which is giving the correct output in Linux environment but not in my Windows 10 PC.

The code is as follows:

package main

import (
    "bufio"
    "fmt"
    "os"
    "strconv"
    "strings"
)

func main() {
    reader := bufio.NewReader(os.Stdin)
    fmt.Print("Enter text: ")
    text, _ := reader.ReadString('
')
    tarr := strings.Split(strings.Trim(text, "
"), " ")

    for i := 0; i < len(tarr); i++ {
        num, _ := strconv.ParseInt(tarr[i], 10, 32)
        fmt.Println(num)
    }

    fmt.Println(tarr)
    reader.ReadString('
')
}

If I enter 1 2 3 as input from the terminal, I am getting the following output in Windows 10 (go version go1.12.5 windows/amd64):

1
2
0
]1 2 3

I am getting the following output in Linux Elementary OS (go version go1.12.5 linux/amd64)

1
2
3
[1 2 3]

Can anyone explain why this is happening?

Answer 1

While UNIX (and Linux) have a line ending of Windows has a line ending of . This means that the line you've read on Linux is 1 2 3 while on Windows it is 1 2 3 . If you now remove the (i.e. strings.Trim(text, " ")) and split by space you get 1, 2 and 3 on Linux but you'll get 1, 2, 3 on Windows.

ParseInt on 3 returns 0 and likely returns an error - which you explicitly ignore. That's why you get the output of 1, 2 and 0 on Windows. Also, the array on Windows will be printed as [1 2 3]. Since sets the output cursor to the beginning of the current line and does not move to the next line (that's what would do) this effectively overrides the initial [ with the final ], resulting on a visible output of ] 1 2 3.