Golang中的身份比较？

Question

I've been trying to build a set of structs that have a base struct as their foundation and variants built on top of that. I've found, however, that there doesn't seem to be a way for the struct to identify itself when the common code is in the base struct. How should I be doing this?

package main

import (
    "fmt"
)

type Base interface {
    IsMe(other Base) bool
}

type Block struct {
}

func (b *Block) IsMe(other Base) bool {
    return b == other
}

type Block2 struct {
    Block
}

func main() {
    b1 := &Block{}
    b2 := &Block2{}
    fmt.Printf("b1.IsMe(b1): %v
", b1.IsMe(b1))
    fmt.Printf("b1.IsMe(b2): %v
", b1.IsMe(b2))
    fmt.Printf("b2.IsMe(b1): %v
", b2.IsMe(b1)) // Wrong result!
    fmt.Printf("b2.IsMe(b2): %v
", b2.IsMe(b2)) // Wrong result!
}

Answer 1

package main

import (
    "fmt"
    "reflect"
)

type Base interface {
    IsMe(other Base) bool
}

type Block struct {
    _ [1]byte // size of struct must be greater than zero
}

func (b *Block) IsMe(other Base) bool {
    x := reflect.ValueOf(b)
    y := reflect.ValueOf(other)
    return x.Pointer() == y.Pointer()
}

type Block2 struct {
    Block // "parent" needs to be first element
}

func main() {
    b1 := &Block{}
    b2 := &Block2{}
    fmt.Printf("b1.IsMe(b1): %v
", b1.IsMe(b1))
    fmt.Printf("b1.IsMe(b2): %v
", b1.IsMe(b2))
    fmt.Printf("b2.IsMe(b1): %v
", b2.IsMe(b1))
    fmt.Printf("b2.IsMe(b2): %v
", b2.IsMe(b2))
}

https://play.golang.org/p/Dx0Ze3euFY