golang与PHP / Ruby的unpack（“ C *”，。）等效吗？

Question

Been searching around, still new to golang, PHP and ruby have an unpack function that unpacks a binary into an array. I'm trying to figure out how to do the following in golang.

$test = "\01\00\02\03";
print_r(unpack("C*", $test)); // [1,0,2,3]

Or

s = "\01\00\02\03"
arr = s.unpack("C*")
p(arr) # [1,0,2,3]

What's the best approach to doing this using golang?

Answer 1

Please note first that your PHP string of "\01\00\02\03" is a string consisting of the 4 bytes \x01,\x00, \x02, \x03 since the "\01" are interpreted as octal. See the documentation for double quoted strings for details.

In Go the syntax \01 is not correct. As in C an octal sequence is required to have 3 digits, i.e. \001. Thus, the PHP string "\01\00\02\03" is in Go "\001\000\002\003" (which would also work in PHP). With this in mind unpacking is easy and no special function like unpack is needed for this:

package main
import "fmt"
func main() {
    s := "\001\000\002\003"
    b := []byte(s)
    fmt.Print(b)
}

Output:

[1 0 2 3]