执行：使用strconv.String转换字符串为float返回0

Question

I have the following code:

reader := bufio.NewReader(os.Stdin)
fmt.Print("room: width x length: ")

inStr, _ := reader.ReadString('
')
result := strings.Split(inStr, "x")

string1, _ := strconv.ParseFloat(result[0], 64)
string2, _ := strconv.ParseFloat(result[1], 64)
fmt.Print(string2)

At the last print statement, if i print string1 it returns the right value, but if i try to print string2 it returns 0, no matter what value i input to the console.

Does anyone know why this is happening? Thanks!

Answer 1

Replace

result := strings.Split(inStr, "x")

with

result := strings.Split(strings.TrimSpace(inStr), "x")

As string contains so your second array element contains it too.

Also I really suggest to look at error messages before posting such kind of questions. You could see strconv.ParseFloat: parsing "23 ": invalid syntax as result of next code

string2, err := strconv.ParseFloat(result[1], 64)
if err != nil {
    fmt.Println(e)
}