通过正则表达式在go中拆分输入字符串

Question

How can I split input strings below by regex in Go? Examples of strings:

I know how to split by dot, but how can I avoid splitting in quotes?

"a.b.c.d" -> ["a", "b", "c", "d"]
"a."b.c".d" -> ["a", "b.c", "d"]
"a.'b.c'.d" -> ["a", "b.c", "d"]

Answer 1

Here is another option with a somewhat less hacky regex. It uses the trash bin trick. So the real data is on the (first and second) capturing groups.

It works even with nested quotes like this: "a.'b.c'.d.e."f.g.h"" as long as there is not a recursion of 2 or more levels (as in here: "a.'b."c.d"'", quotes inside quotes inside quotes).

The regex is this: ^"|['"](\w+(?:\.\w+)*)['"]|(\w+)

And the code:

package main

import (
    "regexp"
    "fmt"
)

func main() {
    var re = regexp.MustCompile(`^"|['"](\w+(?:\.\w+)*)['"]|(\w+)`)
    var str = `"a.'b.c'.d.e."f.g.h""`

    result := re.FindAllStringSubmatch(str, -1)
    for _, m := range result {
        if (m[1] != "" || m[2] != "") {
            fmt.Print(m[1] + m[2] + "
")
        }
    }
}

Input:

"a.'b.c'.d.e."f.g.h""

Output:

a
b.c
d
e
f.g.h