duancong2965 2017-08-17 16:56
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Golang并发问题

I am learning Golang concurrency and have written a program to display URL's in order. I expect the code to return
http://bing.com* http://google.com*

But it always returns http:/google.com*** . As if the variable is being overwritten.Since i am using goroutines i would expect it to return both values at the sametime.

func check(u string) string {
tmpres := u+"*****"
return tmpres
}

func IsReachable(url string) string {
ch := make(chan string, 1)
go func() { 

    ch <- check(url) 

     }()
select {
case reachable := <-ch:
    // use err and reply
    return reachable
case <-time.After(3* time.Second):
    // call timed out
    return "none"
}
   }



func main() {

var urls = []string{
  "http://bing.com/",
  "http://google.com/",
}

for _, url := range urls {
    go func() {
     fmt.Println(IsReachable(url)) 
     }()
}
time.Sleep(1 * time.Second)
  }
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1条回答 默认 最新

  • doudi5892 2017-08-17 17:02
    关注

    Two problems. First, you've created a race condition. By closing over the loop variable, you're sharing it between the thread running the loop and the thread running the goroutine, which is causing your described problem: by the time the goroutine that was started for the first URL tries to run, the value of the variable has changed. You need to either copy it to a local variable, or pass it as an argument, e.g.:

    for _, url := range urls {
        go func(url string) {
         fmt.Println(IsReachable(url)) 
         }(url)
    }
    

    Second, you said you wanted to display them "in order", which is not a goal generally compatible with concurrency/parallism, because you cannot control the order of parallel operations. If you want them in order, you should do them in order in a single thread. Otherwise, you'll have to collect the results, wait for all them to come back, then sort the results back into the desired order before printing them.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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