指针字符串切片（* [] string）的Cgo指针传递规则？

Question

Can I pass *[]string to C from Go and then append to the string slice, or is it violating the pointer passing spec?

Go code may pass a Go pointer to C, provided the Go memory to which it points does not contain any Go pointers.

Example code:

package main

/*
extern void go_callback(void*, char*);

static inline void callback(void* stringSliceGoPointer) {
    go_callback(stringSliceGoPointer, "foobar");
}
*/
import "C"

import (
    "fmt"
    "unsafe"
)

func main() {
    a := make([]string, 0)
    C.callback(unsafe.Pointer(&a)) 
    fmt.Println(a[0]) // outputs foobar
}

//export go_callback
func go_callback(stringSliceGoPointer unsafe.Pointer, msg *C.char) {
    slice := (*[]string)(stringSliceGoPointer)
    *slice = append(*slice, C.GoString(msg))
}

Answer 1

Passing a *[]string to C is not allowed because the memory pointed to contains strings and strings contain pointers. As the cgo docs say (emphasis mine)

Note that values of some Go types, other than the type's zero value, always include Go pointers. This is true of string, slice, interface, channel, map, and function types.

One way to overcome this is to refer to the []string more indirectly so only Go code actually knows its address. For example:

package main

/*
extern void go_callback(int, char*);

static inline void callback(int stringSliceRef) {
    go_callback(stringSliceRef, "foobar");
}
*/
import "C"

import (
    "fmt"
)

// If you need to use these values concurrently,
// you'll need more code to protect this.
var stringSlices = make([][]string, 10)

func main() {
    C.callback(0) 
    fmt.Println(stringSlices[0][0]) // outputs foobar
}

//export go_callback
func go_callback(ref C.int, msg *C.char) {
    i := int(ref)
    stringSlices[i] = append(stringSlices[i], C.GoString(msg))
}