drd0833 2017-11-03 04:25 采纳率: 100%
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Go中的非指针错误,不确定是什么意思

I have a function that takes a json decoder and an interface as its arguements, and i am decoding to a struct that is passed on the interface. Like so:

func DecodeJSON(decoder *json.Decoder, i interface{}) bool {
    if c, ok := i.(User); ok {
        err := decoder.Decode(c)
        if err != nil {
            fmt.Println(err)
            return false //err is not nil
        }
    }
    return false
}

Usage of the function:

// Register test
func HandleRequest(w rest.ResponseWriter, r *rest.Request) {

    decoder := json.NewDecoder(r.Body)
    user := User{}
    if DecodeJSON(decoder, user) {    
        fmt.Println("success")
}

Error i am getting:

json: Unmarshal(non-pointer main.User)

Bit confused by this message since my DecodeJSON is not taking a pointer for user. So am not sure what i have done wrong with my code. Hope some one can explain so i can understand my mistake.

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2条回答 默认 最新

  • douxin1884 2017-11-03 05:06
    关注

    You need to use a pointer to a user to decode the data in, otherwise the decoded data gets decoded in a copy of the object that gets deleted when the function returns.

    func DecodeJSON(decoder *json.Decoder, i interface{}) bool {
        if c, ok := i.(*User); ok {
            err := decoder.Decode(c)
            if err != nil {
                fmt.Println(err)
                return false //err is not nil
            }
        }
        return false
    }
    
    // Register test
    func HandleRequest(w rest.ResponseWriter, r *rest.Request) {
    
        decoder := json.NewDecoder(r.Body)
        user := &User{}
        if DecodeJSON(decoder, user) {    
            fmt.Println("success")
    }
    

    Leave the interface parameter as is, just use a pointer when you pass the User and when you get the user from the interface.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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