Note that since every "row" in a 2D slice may have arbitrary length, you should check the length of each of the corresponding rows (having the same index) if they are equal.
Here's a function that does that:
func match(m1, m2 [][]int) bool {
if len(m1) != len(m2) {
return false
}
for i, row1 := range m1 {
row2 := m2[i]
if len(row1) != len(row2) {
return false
}
}
return true
}
See usage examples:
m1 := [][]int{{1, 2, 3}, {4, 5, 6}}
m2 := [][]int{{7, 8, 9}, {10, 11, 12}}
fmt.Println(match(m1, m2))
m1 = [][]int{{1, 2, 3}, {4, 5, 6, 7, 8}}
m2 = [][]int{{7, 8, 9}, {10, 11, 12, 12, 13}}
fmt.Println(match(m1, m2))
m1 = [][]int{{1, 2, 3}, {4, 5, 6, 7, 8}}
m2 = [][]int{{7, 8, 9}, {10, 11, 12, 12}}
fmt.Println(match(m1, m2))
m1 = [][]int{{1, 2, 3}}
m2 = [][]int{{7, 8, 9}, {10, 11, 12, 12}}
fmt.Println(match(m1, m2))
Output (as expected):
true
true
false
false
Simplification for Special case:
If you have guarantee that in all of your matrices all rows have the same length, you can make a big simplification: in this case if number of rows matches, it's enough to compare the length of one of the rows only from each matrices, practically the first row.
It could look like this:
func match2(m1, m2 [][]int) bool {
if len(m1) != len(m2) {
return false
}
return len(m1) == 0 || len(m1[0]) == len(m2[0])
}
Testing it:
m1 = [][]int{{1, 2, 3}, {4, 5, 6}}
m2 = [][]int{{7, 8, 9}, {10, 11, 12}}
fmt.Println(match2(m1, m2))
m1 = [][]int{{1, 2, 3, 4}, {5, 6, 7, 8}}
m2 = [][]int{{7, 8, 9}, {10, 11, 12}}
fmt.Println(match2(m1, m2))
Output:
true
false
Try these on the <kbd>Go Playground</kbd>.