duanji4870 2018-06-02 13:48
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Golang主要功能中的两个.RUN()函数

A Go newbie so please forgive if the answer to my question is really simple but I have spent nearly four hours trying to make Facktory Go Worker up and running with API being written with Gin Framework. Here is how my main function looks like:

func main() {
    r := gin.Default()
    r.GET("/ping", func(c *gin.Context) {

        go func() {
             for i := 0; i < 10000; i++ {
                produce() // Function to push jobs to Faktory
              }
        }()
        c.JSON(200, gin.H{
            "message": "pong",
        })

    })
    r.Run() // listen and serve on 0.0.0.0:8080

    mgr := worker.NewManager()

    mgr.Register("SomeJob", someFunc)


    // use up to N goroutines to execute jobs
    mgr.Concurrency = 20

    // pull jobs from these queues, in this order of precedence
    mgr.Queues = []string{"critical", "default", "bulk"}

    // Start processing jobs, this method does not return
    mgr.Run()

}

Out of mgr.Run() and r.Run() whichever is called first ends up blocking the other one so if mgr.Run() is placed before r.Run() the jobs are pulled from faktory server and executed but the server does not boot and it is the other way around if r.Run() is called before mgr.Run(). Any help in solving this or pointing me to the direction to sort this out myself will be highly appreciated.

The faktory server is running in a docker container using this image but the jobs are pushed to faktory server so I do not think there are any configuration issues here.

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  • dongtan8979 2018-06-03 05:29
    关注

    Since both calls are blocking you need to execute the first one, whichever you want that to be, in a separate goroutine. The second one should be executed normally so that it blocks main from exiting.

    func main() {
        // ...
        go r.Run()
    
        // ...
        mgr.Run()
    }
    

    or

    func main() {
        // ...
        go mgr.Run()
    
        // ...
        r.Run()
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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