如何将zip文件从字节数组写入磁盘

Question

I'm downloading a zip file from S3 in Go like so:

buff := &aws.WriteAtBuffer{}
downloader := s3manager.NewDownloader(session.New(config))
_, err := downloader.Download(buff, &input)
if err != nil {
    log.Println(err)
    return err
}

data := buff.Bytes()

I send 'data' to a client that's written in Python3, and need to convert this byte array back to a zip file and put it in a specified directory. I've tried this:

file_bytes = msg_obj["Params"]

try:
    zf = zipfile.ZipFile(file_bytes, "r")
    for fileinfo in zf.infolist():
        print(zf.read(fileinfo).decode('ascii'))
except: print("Err:", sys.exc_info()[0])

But I get this error:

OSError: [Errno 36] File name too long"

I just want to 'rebuild' the zip file and save it to a directory.

Answer 1

I figured out how to do this. In go, you'll want to base64 encode it (as a string).

buff := &aws.WriteAtBuffer{}
downloader := s3manager.NewDownloader(session.New(config))
_, err := downloader.Download(buff, &input)
if err != nil {
    log.Println(err)
    return err
}

data := b64.StdEncoding.EncodeToString(buff.Bytes())

Then in python it's as simple as this (where 'file_bytes' is the base64 encoded string):

d = base64.b64decode(file_bytes)
f = open('home/update_file', 'wb')
f.write(d)
f.close()

And bam, you have a reassembled zip file.