如何通过Golang解码具有特殊字符的xml

Question

For example, if the xml is simple:

<p>this is a test xml</p>

Then I can use struct like this:

type Dummy struct { XMLName xml.Name `xml:"p"` Value string `xml:",chardata"` }

But if the xml has special character, like

<p>this is a test < xml & </p>

I used the same struct and it caused error, and it seems nothing to do with struct, because I use interface{} and it caused error the same.

I read the document of package "encoding/xml" but cannot find the right way.

Does anyone know how to do this?

Answer 1

This XML is not well-formed. It contain syntax error because character & has a special meaning. If you need to insert if as a symbol itself change it with &. After parsing it will be replaced back to usual &.

The same rule applies to < - it should be replaced with <.

  <p>this is a test <gt; xml &amp; </p>

This is the general rule for all XML parsers and encoders. Any other XML system awaits similar behavior.