用Go编写打包二进制文件会产生与此Python相同输出的惯用方式是什么？

Question

I'm trying to figure out how the best way to write a binary file in Go that corresponds with the following Python:

import struct
f = open('tst.bin', 'wb')
fmt = 'iih'
f.write(struct.pack(fmt,4, 185765, 1020))
f.close()

I have been tinkering with some of the examples I've seen on Github.com and a few other sources but I can't seem to get anything working correctly. What is the idiomatic way to do this sort of thing in Go?

Here is how I am accomplishing this now (Golang):

package main
import (
        "fmt"
        "os"
        "encoding/binary"
        )


func main() {
        fp, err := os.Create("tst.bin")

        if err != nil {
                panic(err)
        }

        defer fp.Close()

        aBuf := make([]byte, 4)
        bBuf := make([]byte, 4)
        cBuf := make([]byte, 2)

        binary.LittleEndian.PutUint32(aBuf, 4)
        binary.LittleEndian.PutUint32(bBuf, 185765)
        binary.LittleEndian.PutUint16(cBuf, 1020)

        binary.Write(fp, binary.LittleEndian, aBuf)
        binary.Write(fp, binary.LittleEndian, bBuf)
        binary.Write(fp, binary.LittleEndian, cBuf)
}

Verified with this Python:

import numpy as np

data = np.fromfile('tst.bin', dtype='i4,i4,i2')

print(data)

Answer 1

After a little more tinkering and some feedback on another question I was able to come up with this (seems much cleaner but will post feedback on performance after testing with generating some large files):

package main
import (
        "os"
        "encoding/binary"
        )

type binData struct {
    A int32
    B int32
    C int16
}

func main() {
        fp, err := os.Create("tst.bin")

        if err != nil {
                panic(err)
        }

        defer fp.Close()
        bd := binData{A:4, B:185765, C:1020}

        binary.Write(fp, binary.LittleEndian, &bd)
}