dongzhazhuo0572 2016-01-16 03:42
浏览 66
已采纳

defineRuneInternal和encodeRuneInStringInternal有什么区别

In golang's std package, "func decodeRuneInternal" and "func decodeRuneInStringInternal" are the same except the args, that is:

func decodeRuneInternal(p []byte) (r rune, size int, short bool)
func decodeRuneInStringInternal(s string) (r rune, size int, short bool)

Why not just define decodeRuneInStringInternal as:

func decodeRuneInStringInternal(s string) (r rune, size int, short bool) {
    return decodeRuneInternal([]byte(s)) (r rune, size int, short bool)
}

in utf8.go, decodeRuneInStringInternal's implementations is the same with decodeRuneInternal.

WHY?

  • 写回答

1条回答 默认 最新

  • douhu3424 2016-01-16 03:51
    关注

    The two functions avoid the memory allocation in the conversion []byte(s) in the case where the string function wraps the []byte function or the memory allocation in the conversion string(p) in the case where the []byte function wraps the string function.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 相敏解调 matlab
  • ¥15 求lingo代码和思路
  • ¥15 公交车和无人机协同运输
  • ¥15 stm32代码移植没反应
  • ¥15 matlab基于pde算法图像修复,为什么只能对示例图像有效
  • ¥100 连续两帧图像高速减法
  • ¥15 如何绘制动力学系统的相图
  • ¥15 对接wps接口实现获取元数据
  • ¥20 给自己本科IT专业毕业的妹m找个实习工作
  • ¥15 用友U8:向一个无法连接的网络尝试了一个套接字操作,如何解决?