dongmi1941 2018-08-22 07:43
浏览 33
已采纳

如何转换函数类型? [关闭]

I want to use upCase as a variable in expend, But it said "Cannot use 'upCase(s1)'(type string) as type func(string) string. how can I to convert upCase type? Or what do I need do to make the wrong disappear?

package main

import (
    "fmt"
    "strings"
)

func main() {
    s := "test func"
    s1 := ""
    test := expand(s, upCase(s1))
    fmt.Print(test)
}
func expand(s string, f func(string) string) string {
    s1 := "test"
    var s2 string
    if strings.Contains(s, s1) {
        // todo 字符串中s1的值更改为f(s1)的值
        s1 = f(s1)
        strings.Replace(s1, s, s2, -1)
    } else {
        return ""
    }
    return s2
}

func upCase(s string) string {
    s = strings.ToUpper(s)
    return s
}
  • 写回答

1条回答 默认 最新

  • duanmao2774 2018-08-22 07:46
    关注

    You are calling the upCase function in your call to expand (so it returns a string that you pass to your expand function). You need to pass in the function:

    test := expand(s, upCase)
    

    Your current code test := expand(s, upCase(s1)) is the same as doing:

    v := upCase(s1)
    test := expand(s, v)
    

    I.e, you are just calling upCase(s1) that returns a string, and you pass that string to expand , which expects a function, not a string as its 2. argument.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 微信会员卡等级和折扣规则
  • ¥15 微信公众平台自制会员卡可以通过收款码收款码收款进行自动积分吗
  • ¥15 随身WiFi网络灯亮但是没有网络,如何解决?
  • ¥15 gdf格式的脑电数据如何处理matlab
  • ¥20 重新写的代码替换了之后运行hbuliderx就这样了
  • ¥100 监控抖音用户作品更新可以微信公众号提醒
  • ¥15 UE5 如何可以不渲染HDRIBackdrop背景
  • ¥70 2048小游戏毕设项目
  • ¥20 mysql架构,按照姓名分表
  • ¥15 MATLAB实现区间[a,b]上的Gauss-Legendre积分