duanhui1869 2015-07-17 19:12
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如何使用从接口实现的方法更改结构中变量的指针

Edit: For everyone suggesting using a pointer receiver in the function: By changing the method to have a pointer receiver, the structure no longer implements the interface. I have a image at the bottom of my question showing that.

I am trying to make a setter that will mutate the pointer of a variable in a struct with a method implemented from an interface.

package main

import "fmt"

func main() {
    i := 1
    b := BlahImpl {id:&i}

    fmt.Println(b.ID())
    j := 2
    b.SetID(&j)

    fmt.Println(b.ID())
}

type BlahInterface interface {
    SetID(*int)
    ID() int
}

type BlahImpl struct {
    id *int
}

func (b BlahImpl) SetID(i *int) {
    b.id = i
}

func (b BlahImpl) ID() int {
    return *b.id
}

The current output is:

1
1

But I would like:

1
2

When I use pointer receiver I get this error because the struct is no longer implementing the interface. error

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1条回答 默认 最新

  • doujue9767 2015-07-17 19:33
    关注

    Well, to be honest I do not quite get why it works this way, but this works as you want it to:

    package main
    
    import "fmt"
    
    func main() {
        i := 1
        b := BlahImpl{id: &i}
    
        fmt.Println(b.ID())
        j := 2
        b.SetID(&j)
    
        fmt.Println(b.ID())
    }
    
    type BlahInterface interface {
        SetID(*int)
        ID() int
    }
    
    type BlahImpl struct {
        id *int
    }
    
    func (b *BlahImpl) SetID(i *int) {
        b.id = i
    }
    
    func (b *BlahImpl) ID() int {
        return *b.id
    }
    

    The difference is how the structure's methods are defined. I've added * before the name so reference on the structure is passed into the method. It looks like without * the method gets copy of the struct so the modification does not work.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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