doulao2029 2017-12-17 17:37
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获取Golang中给定文件路径的目录名称(不是路径)

By using the path/filepath package with the following example, you can get the full directory path from a file path.

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    // Output: /path/to/dir
    fmt.Println(filepath.Dir("/path//to/dir/file.ext"))
}

But is there a Parent function to get the dir from the path? (which is the name of the directory of the file):

// The `Parent` is what I want,
// and this is a pseudo-code example, this won't actually work.
//
// Output: dir
fmt.Println(filepath.Parent("/path//to/dir/file.ext"))

If it can't be done with the functions, how do I get the parent's name with RegExp?

  • 写回答

1条回答 默认 最新

  • dongyingla8668 2017-12-17 17:46
    关注

    You can use filepath.Base to get the last element of the directory. For example:

    package main
    
    import (
        "fmt"
        "path/filepath"
    )
    
    func main() {
        paths := []string{
            "/home/arnie/amelia.jpg",
            "/mnt/photos/",
            "rabbit.jpg",
            "/usr/local//go",
        }
        for _, p := range paths {
            dir := filepath.Dir(p)
            parent := filepath.Base(dir)
            fmt.Printf("input: %q
    \tdir: %q
    \tparent: %q
    ", p, dir, parent)
        }
    }
    

    Returns:

    input: "/home/arnie/amelia.jpg"
        dir: "/home/arnie"
        parent: "arnie"
    input: "/mnt/photos/"
        dir: "/mnt/photos"
        parent: "photos"
    input: "rabbit.jpg"
        dir: "."
        parent: "."
    input: "/usr/local//go"
        dir: "/usr/local"
        parent: "local"
    

    (example adapted from the filepath examples)

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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