golang使struct T实现I但不是* T

Question

I have a struct T that implements an interface I, but I want *T to not implement the interface. Is this possible?

That is, this should compile fine:

var obj I = T{}

but this should generate a compile error:

var obj I = &T{}

The reason is that it is a common mistake in my codebase to accidentally use *T as a certain interface I when it is expected that only T will be used.

Answer 1

Not possible. From the spec (emphasis mine):

A type may have a method set associated with it. The method set of an interface type is its interface. The method set of any other type T consists of all methods declared with receiver type T. The method set of the corresponding pointer type *T is the set of all methods declared with receiver *T or T (that is, it also contains the method set of T).