Since parameter e
is int
, why not just return an int64
? Is there any special reason for this?
为什么math.Pow10(e int)返回float64而不是int64?
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1条回答 默认 最新
- douliao8402 2017-02-13 09:12关注
2 reasons:
First, the parameter may be negative too, in which case the result is a fraction number between
0
and1
, so afloat64
return value is not just justified but needed.fmt.Println(math.Pow10(-1))
Output (try it on the Go Playground):
0.1
Second, almost* every function of the
math
package returns value(s) of typefloat64
, adding one that doesn't would break "consistency".[*] Few exceptions include functions like
Float32frombits()
andllogb()
where the deviation is justified.本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报
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