将字符串的错误值丢掉进行int转换

Question

I have a Go program that I simply want to convert a string to an int. I understand the function:

val, err := strconv.Atoi(myValueAsAString)

works and I can check the error by the following:

if err != nil {
    //handle error
}

But what if I am 100% the string will be a number, and I want to convert it to an int in an if statement, like the following:

if 45 + strconv.Atoi(value) >= 90 {
    //do something
}

But strconv.Atoi also returns an error value as well, so how can I throw that away and essentially do what I did above, without having to define the variable above the if statement and use it in the if statement. I'm not sure if this is possible or not, but I would love to know.

Answer 1

1. Create a wrapper function that discards the error result:

func atoi(s string) int {
    value, _ := strconv.Atoi(s)
    return value
}

if 45 + atoi(value) >= 90 {
    //do something
}

1. Or, do the conversion as a statement before the if and ignore the error result:

if i, _ := strconv.Atoi(value); 45 + i >= 90 {
    // do something
}