前端传过来的参数可以只要id和name,也可以全部都要!问题是现在代码方面如果传了两个值id和name就会报错,有解决的办法嘛?

Question

前端传过来的参数可以只要id和name,也可以全部都要!问题是现在代码方面如果传了两个值id和name就会报错,传5个值是正常的,我要怎么做判断,让传两个值跑另一段代码呢?

@BussinessLog()
    @ApiOperation(value = "编辑菜单操作")
    @PutMapping(value = "/updateLdTemplate")
    public Object updateLdTemplate(@ApiJsonObject(name = "编辑菜单逻辑设备", value = {
            @ApiJsonProperty(name = "id", example = "40", value = "逻辑设备id", dataType = "long", required = true),
            @ApiJsonProperty(name = "name", example = "配电柜", value = "逻辑设备模板名", dataType = "string", required = true),
            @ApiJsonProperty(name = "ipAddress", example = "192.168.31.4", value = "放电装置IP地址设置", dataType = "string", required = true),
            @ApiJsonProperty(name = "ipMask", example = "192.168.31.1", value = "放电装置IP掩码设置", dataType = "string", required = true),
            @ApiJsonProperty(name = "ipGateway", example = "255.255.255.0", value = "放电装置IP网关设置", dataType = "string", required = true)
    }) @ApiParam(value = "逻辑设备") @RequestBody Map<String, Object> map) {
        Long id = Long.parseLong(map.get("id").toString());
        String ipAddress = String.valueOf(map.get("ipAddress").toString());
        String ipGateway = String.valueOf(map.get("ipGateway").toString());
        String ipMask = String.valueOf(map.get("ipMask").toString());
        String name = map.get("name").toString();
        return systemMenuService.updateLdTemplate(id, ipAddress, ipGateway, ipMask, name);
    }

Answer 1

你把toString都去掉，用的时候判断是不是null，不是null再toString，这样你就可以随便传参了