python Flask框架
Python： 2.7.9
Flask ： 0.10.1
通过表单提交的方式，把本地图片上传到A服务器，但是A服务器不要保存此图片，而是要通过A服务器把图片提交到B服务器、C服务器、D服务器上去。如何实现？
了解到python的cStingIO、StringIO 模块 可以实现此功能，搜索了一天了，还是不懂如何应用到此处。请各位不吝赐教！
A服务器上的代码：
import os
from flask import Flask, request, redirect, url_for
from werkzeug import secure_filename
import requests
import cStringIO
from cStringIO import StringIO
import Image
UPLOAD_FOLDER = 'c:\uploads_1'
if not os.path.exists(UPLOAD_FOLDER):
os.makedirs(UPLOAD_FOLDER)
else:
pass
ALLOWED_EXTENSIONS = set(['pdf', 'png', 'jpg', 'jpeg', 'gif'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
if request.method == 'POST':
upload_files = request.files.getlist('file[]')
filenames = []
for file in upload_files:
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename)) #使用StringIO时，请注释掉此行
filenames.append(filename)
data = {'file[]': open(os.path.join(app.config['UPLOAD_FOLDER'],filename), 'rb')}
#buf = cStringIO.StringIO(file)
#buf.seek(0)
#buf_img = buf.read()
#data = {'file[]': files=buf_img}
r = requests.post('http://127.0.0.1:5000/',files=data)
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file multiple="" name="file[]">
<input type=submit value=Upload>
</form>
'''
if __name__ == '__main__':
app.run(debug=True,host='0.0.0.0',port=8000)
B服务器上的代码：
import os
from flask import Flask, request, redirect, url_for
from werkzeug import secure_filename
import requests
UPLOAD_FOLDER = 'c:\uploads_2'
if not os.path.exists(UPLOAD_FOLDER):
os.makedirs(UPLOAD_FOLDER)
else:
pass
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
if request.method == 'POST':
upload_files = request.files.getlist('file[]')
filenames = []
for file in upload_files:
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
filenames.append(filename)
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file multiple="" name="file[]">
<input type=submit value=Upload>
</form>
'''
if __name__ == '__main__':
app.run(debug=True,host='0.0.0.0')
