C语言中指针和地址的问题

Question

想问一下以下程序中printf输出的都是什么数字，与数组中的数字和位置有什么关系

#include

int main(int argc, const char * argv[]) {

int a[5] = {3,4,8,9,10};
double *p = (double *)&a;

printf("%d\n",(double *)p);

int *q = p;
printf("%d\n",*q);



//
int b[7] = {3,4,8,9,10,11,12};
double *x = (double *)&b;

printf("%d\n", *x);

int *y = x;
printf("%d\n",*y);

//
int d[6] = {3,4,8,9,10,11};
double *j = (double *)&d;

printf("%d\n",*j);

int *k = j;
printf("%d\n",*k);


//

int c[5] = {3,4,8,9,10};
double *n = (double *)&c;

printf("%d\n",*n);

int *m = n;
printf("%d\n",*m);

return 0;

}

Answer 1

比如 double *p = (double *)&a; p指向了一个int数组，那么编译器知道p的类型是int型，那么p+1就会移动sizeof(int)长度，指向了下一个元素