菜鸟的函数哪里出了问题？（C语言函数返回指针的题型）

Question

实现功能，一旦某一组里面有一个成绩在line_num以下的，就把这一组的数字都输出。
代码如下，改了好久还是没发现问题出现在哪里。
求教高手指点，非常感谢 >< ~

# include<stdio.h>

int main(){
    float *search(float *(pointer)[3], float line);

    float score[][3]={
        {23, 56, 89},
        {56, 12, 91},
        {81, 73, 80},
        {34, 62, 95}
    };
    float line_num;
    int i;
    float *p_addr;

    printf("input the limit line:\n");
    scanf("%f", &line_num);
    p_addr=search(score, line_num);
    printf("the student's scores are listed here:\n");
    for(i=0; i<3; i++) printf("%f\t", *(p_addr+i));
    putchar('\n');

    return 0;
}

float *search(float *(pointer)[4], float line){
    float *p_addr;
    int i, j;

    for(i=0; i<4; i++){
        for(j=0; j<3; j++){
            if(*(*(pointer+i)+j)<line) return p_addr=*(pointer+i);
        }
    }
} 

Answer 1

好了，帮你改好了，请采纳吧……

#include <stdio.h>
#include <stdlib.h>

float *search(float pointer[][3], float line);

int main() {

    float score[][3] = {
        { 23, 56, 89 },
        { 56, 12, 91 },
        { 81, 73, 80 },
        { 34, 62, 95 }
    };
    float line_num;
    int i;
    float *p_addr;

    printf("input the limit line:\n");
    scanf("%f", &line_num);
    p_addr = search(score, line_num);
    printf("the student's scores are listed here:\n");
    for (i = 0; i<3; i++) printf("%f\t", *(p_addr + i));
    putchar('\n');

    return 0;
}

float *search(float pointer[][3], float line) {
    float *p_addr;
    int i, j;

    for (i = 0; i<4; i++) {
        for (j = 0; j<3; j++) {
            if (*(*(pointer + i) + j)<line)
                return p_addr = *(pointer + i);
        }
    }
}

如果输入为60，由于你的输出为浮点型，所以输出是23.000000 56.000000 89.000000