2 ssummeraw ssummeraw 于 2013.05.03 14:11 提问

如何从sqlite数据库中获取数据并显示在listview中?

在登录页面后,我想在listview中把Apple显示成A,Boy显示成B等等,直到F。但是在程序中当我完全登录后,只有登录表成功创建,主菜单还是没有创建。
我想在test database中创建主菜单,然后我想从主菜单表(mainmenu table)中获取数据再显示在listview中。
我使用了下面的代码:

 if(username.length()>0&&password.length()>0)
        {
            SQLiteAdapter db=new SQLiteAdapter(Main.this);
            db.openToWrite();
            if(db.Login(username,password))
            {
                System.out.println("goutham");
                Intent intent=new Intent(getApplicationContext(),ExampleActivity.class);

                startActivity(intent);
            } 

SQLiteAdapter.java

}

public Cursor queueAll() {
    String[] columns = new String[] { KEY_ID, KEY_CONTENT };
    Cursor cursor = sqLiteDatabase.query(MYDATABASE_TABLE, columns, null,
            null, null, null, null);

    return cursor;
}

private static class SQLiteHelper extends SQLiteOpenHelper {

    public SQLiteHelper(Context context, String name,
            CursorFactory factory, int version) {
        super(context, name, factory, version);
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        // TODO Auto-generated method stub
        db.execSQL(SCRIPT_CREATE_DATABASE);
        db.execSQL(DATABASE_CREATE);
    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        // TODO Auto-generated method stub

    }

}

public long AddUser(String username, String password) {
    ContentValues initialValues = new ContentValues();
    initialValues.put(KEY_USERNAME, username);
    initialValues.put(KEY_PASSWORD, password);
    return sqLiteDatabase.insert(DATABASE_TABLE, null, initialValues);

}

public boolean Login(String username, String password) {
    // TODO Auto-generated method stub
    Cursor mCursor = sqLiteDatabase.rawQuery("SELECT * FROM "
            + DATABASE_TABLE + " WHERE username=? AND password=?",
            new String[] { username, password });
    if (mCursor != null) {
        if (mCursor.getCount() > 0) {
            return true;
        }
    }
    return false;
}

 }

ExampleActivity.java

 public class ExampleActivity extends Activity {
private SQLiteAdapter mySQLiteAdapter;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    ListView listContent = (ListView) findViewById(R.id.contentlist);

    /*
     * Create/Open a SQLite database and fill with dummy content and close
     * it
     */
    mySQLiteAdapter = new SQLiteAdapter(this);
    mySQLiteAdapter.openToWrite();
    // mySQLiteAdapter.deleteAll();

    mySQLiteAdapter.insert("A for Apply");
    mySQLiteAdapter.insert("B for Boy");
    mySQLiteAdapter.insert("C for Cat");
    mySQLiteAdapter.insert("D for Dog");
    mySQLiteAdapter.insert("E for Egg");
    mySQLiteAdapter.insert("F for Fish");

    mySQLiteAdapter.close();

    /*
     * Open the same SQLite database and read all it's content.
     */
    mySQLiteAdapter = new SQLiteAdapter(this);
    mySQLiteAdapter.openToRead();

    Cursor cursor = mySQLiteAdapter.queueAll();
    startManagingCursor(cursor);

    String[] from = new String[] { SQLiteAdapter.KEY_CONTENT };
    int[] to = new int[] { R.id.text };

    SimpleCursorAdapter cursorAdapter = new SimpleCursorAdapter(this,
            R.layout.row, cursor, from, to);

    listContent.setAdapter(cursorAdapter);

    mySQLiteAdapter.close();

}
}

运行程序后,登录表在数据库中创建了,但是主菜单表没有创建。运行程序后,显示一个错误:

sqlite returned code=1 no such a table in MY_TABLE

1个回答

curie_87
curie_87   2013.05.06 10:26
已采纳

Database class:

public String getData1() throws SQLException{
        // TODO Auto-generated method stub
        String[] columns1 = new String[] { KEY_DATE };
        Cursor c1 = ourDatabase.query(DATABASE_MARKSTABLE, columns1, null, null, null,
                null, KEY_ENDINGTIME+" DESC", " 30");
        String result1 = "";

        int isName = c1.getColumnIndex(KEY_DATE);

        for (c1.moveToFirst(); !c1.isAfterLast(); c1.moveToNext()) {

            result1 = result1 + c1.getString(isName)
                    + "  " + "\n";
         }
        c1.close();
        return result1;
     }
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