坏人未变坏 2017-07-21 07:19 采纳率: 46.2%
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如何将三段sql语句存到一个结果集中返回?

这是我的SQL语句:

             select
                                    a.amount as suixi_money,
                                    a.amodanaTime as suixi_tiem,
                                    a.registerMobile as principal_tel_number,
                                    b.type as activity_type,
                                    c.name as query_nickname,
                                    c.mobile as query_tel_number,
                                    c.realName as query_name
                               from tb_activity_record a
                                left join tb_activity b on a.activityId = b.id
                                left join tb_member c on a.memberId = c.id
                        where 1=1
                                and b.uid = '8445e6a4-9341-455b-bfef-81e0b5ed7a1e'
                                and  (
                                c.name like '1%'
                                or c.realName like '1%'
                                or c.mobile like '1%'
                                 )

                            select count(*) from (select distinct memberId from tb_activity_record ) ac


                            select SUM(amount) from tb_activity_record

这三段:
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万分感谢

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12条回答 默认 最新

  • Nothing_katu 2017-07-21 09:50
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     SELECT
        A .amount AS suixi_money,
        A .amodanaTime AS suixi_tiem,
        A .registerMobile AS principal_tel_number,
        b. TYPE AS activity_type,
        c. NAME AS query_nickname,
        c.mobile AS query_tel_number,
        c.realName AS query_name,
    ac.count,
    su.SUM
    FROM
    (select count(*) count from (select distinct memberId from tb_activity_record ) d) ac,
    (select SUM(amount)  SUM from tb_activity_record) su,
        tb_activity_record A
    LEFT JOIN tb_activity b ON A .activityId = b. ID
    LEFT JOIN tb_member c ON A .memberId = c. ID
    
    WHERE
        1 = 1
    AND b. UID = '8445e6a4-9341-455b-bfef-81e0b5ed7a1e'
    AND (
        c. NAME LIKE '1%'
        OR c.realName LIKE '1%'
        OR c.mobile LIKE '1%'
    )
    

    你第一段sql查不出数据啊?

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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