习题7-8 字符串转换成十进制整数 (15分)

Question

代码 求大神指教
#include
int main(void)
{
char str[80];
char str_16[80];
int i=0;
while((str[i]=getchar())!='#')
{
i++;
}
str[i]='\0';

int k=0;
for(int j=0;j<i;j++)
{
    if((str[j]>='0'&&str[j]<='9')||(str[j]>='a'&&str[j]<='f')||(str[j]>='A'&&str[j]<='F'))
    {
        str_16[k]=str[j];
        k++;
    }
}
str_16[k]='\0';

long number=0;
int flag=0,flag2=0;
for(int j=0;j<k;j++)
{
    if(flag==0&&str[j]=='-')
    {
        flag2=1;
    }
    if(str_16[j]>='0'&&str_16[j]<='9')
    {
        flag=1;
        number=number*16+str_16[j]-'0';
    }else if(str_16[j]>='a'&&str_16[j]<='f')
    {
        flag=1;
        number=number*16+str_16[j]-'a'+10;
    }else{
        flag=1;
        number=number*16+str_16[j]-'A'+10;
    }
}
if(flag2==1){
    number=-number;
}
printf("%ld",number);
return 0;

}

Answer 1

http://blog.csdn.net/lgouc/article/details/7534845