℡Wang Yan 2009-06-15 18:04 采纳率: 100%
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是否支持默认参数值?

I came across some Java code that had the following structure:

public MyParameterizedFunction(String param1, int param2)
{
    this(param1, param2, false);
}

public MyParameterizedFunction(String param1, int param2, boolean param3)
{
    //use all three parameters here
}

I know that in C++ I can assign a parameter a default value. For example:

void MyParameterizedFunction(String param1, int param2, bool param3=false);

Does Java support this kind of syntax? Are there any reasons why this two step syntax is preferable?

转载于:https://stackoverflow.com/questions/997482/does-java-support-default-parameter-values

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  • perhaps? 2009-06-15 18:14
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    No, the structure you found is how Java handles it (that is, with overloading instead of default parameters).

    For constructors, See Effective Java: Programming Language Guide's Item 1 tip (Consider static factory methods instead of constructors) if the overloading is getting complicated. For other methods, renaming some cases or using a parameter object can help. This is when you have enough complexity that differentiating is difficult. A definite case is where you have to differentiate using the order of parameters, not just number and type.

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