bytebuffer 的 position问题

Question

public class BytebufferTest{

public static void main(String[] args)throws IOException{
     ByteBuffer bbuffer = ByteBuffer.allocate(10);
     byte[] b1 = new byte[]{'a','b'};
     bbuffer.put(b1);

     System.out.println(bbuffer.position());

     char[] c1 = new char[]{'c','d'};
bbuffer.asCharBuffer().put(c1);

     System.out.println(bbuffer.position());

     buffer.rewind();   
while(bbuffer.hasRemaining()){
     System.out.println((char)bbuffer.get());
}
}

}

请问为什么“System.out.println(bbuffer.position());”输出的position值一样，之后的“'c','d'”不是已经成功存入byterbuffer了吗，为什么position值不相应增加？

谢谢大侠！

[b]问题补充：[/b]
TO：RednaxelaFX

请问大侠这段JavaDoc您是在哪里找到的？我也想拜读下。

Answer 1

[quote="Javadoc"]The content of the new buffer will start at this buffer's current position. Changes to this buffer's content will be visible in the new buffer, and vice versa; [color=red]the two buffers' position, limit, and mark values will be independent[/color].[/quote]
因为asCharBuffer()之后对返回出来的CharBuffer调用put()不会改变原来的ByteBuffer的position，虽然内容是联动的