[size=medium]大家帮我一下吧，我在JE上找了一个JSP取得客户端IP地址的方法，但是我放到JSP网页运行的时候总是出错呢？这是为什么呀。我用的是Tomcat 6.0
[code="java"]public String getIpAddr(HttpServletRequest request) {
String ip = request.getHeader("x-forwarded-for");
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}[/code]
出现了这个错误
[code="java"]An error occurred at line: 11 in the jsp file: /ip.jsp
Illegal modifier for the variable getIpAddr; only final is permitted
8: IP地址
9:
10: <%
11: public String getIpAddr(HttpServletRequest request) {
12: String ip = request.getHeader("x-forwarded-for");
13: if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
14: ip = request.getHeader("Proxy-Client-IP");
An error occurred at line: 11 in the jsp file: /ip.jsp
Syntax error on token "(", ; expected
8: IP地址
9:
10: <%
11: public String getIpAddr(HttpServletRequest request) {
12: String ip = request.getHeader("x-forwarded-for");
13: if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
14: ip = request.getHeader("Proxy-Client-IP");
An error occurred at line: 11 in the jsp file: /ip.jsp
Duplicate local variable request
8: IP地址
9:
10: <%
11: public String getIpAddr(HttpServletRequest request) {
12: String ip = request.getHeader("x-forwarded-for");
13: if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
14: ip = request.getHeader("Proxy-Client-IP");
An error occurred at line: 11 in the jsp file: /ip.jsp
Syntax error on token ")", ; expected
8: IP地址
9:
10: <%
11: public String getIpAddr(HttpServletRequest request) {
12: String ip = request.getHeader("x-forwarded-for");
13: if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
14: ip = request.getHeader("Proxy-Client-IP");
An error occurred at line: 22 in the jsp file: /ip.jsp
Void methods cannot return a value
19: if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
20: ip = request.getRemoteAddr();
21: }
22: return ip;
23: }
24: %>
25:
